ISAC Operator Training Lecture:
Tuning and Slits

Rick Baartman

  What is a beam?

Answer: a group of particles traveling more or less in the same direction.
Q: Why can't they be perfect? I.e. why not travel in exactly the same direction?
Look at an ion source. Atoms are ionized by hitting them hard enough. How hard? Ionization energy is typically on order of 3 eV. So a typical energy before extraction is 3 eV. After extraction, it is 30 keV, but it will still have the same transverse momentum.
../TrainingImages/source.png

  What is beam quality?

Beam has high quality if it is small and its divergence (rate of spreading) is also small.

../TrainingImages/abquality.png
But beam may be high in quality and nevertheless violate these two conditions.

../TrainingImages/cquality.png
So we need a better definition.

  `Phase' space

Particles can be characterized by position (x) and momentum, or direction (q). So on an (x,q) coordinate plane, every particle can be assigned a point. Look at our 3 examples again:

../TrainingImages/abcps.png
Now it is easy to see why case C is high quality even though it corresponds to large, divergent beam. The area it occupies in phase space is zero.
This area is called `emittance'. It is related to entropy: with good practices, it is conserved, but it can increase and it's difficult to make it smaller.
Liouville's theorem: Under the action of conservative forces, emittance is conserved.

  Real life emittances

Besides the (x,q) coordinate plane, there is also the (y,f) coordinate plane. The two emittances are not necessarily the same.
../TrainingImages/duos.png
Also, notice the lack of a well-defined boundary. This means "emittance" is a fuzzy term; sometimes we say e rms, sometimes e90%, etc.

  How does e relate to beam size?

A good emittance from the surface source is about 9 pmm-mrad. The p is there to remind that you must multiply the 9 by p to get phase space area. But actually, the real physics definition of emittance is area divided by p. So for physics formulas, we say
e = 9 mm
(note: 1 mrad=1/1000)
Since this is a 2D quantity, you would probably guess that beam size is proportional to square root of emittance. This is correct. In fact, the half-size a is
a=
Ö
 

bT e
 
,
where b T is a scaling parameter called the `Twiss beta function': it contains the focusing information; it is large where the beam is large and small where the beam is focused to a small spot.

  Examples

At slits 24 and 26, bT=0.85 m, in both H and V directions. Therefore, the half-size a=Ö{9×0.85} mm=2.75 mm, or the correct slit size is 5.5 mm.
At the pre-separator slit (IMS:YSLIT0), bT=0.11 m (horizontally). Therefore, the half-size a=Ö{9×0.11} mm=1.0 mm, or the correct slit size is 2 mm.
At the mass selection slit (IMS:YSLIT11), bT=0.03 m (horizontally). Therefore, the half-size a=Ö{9×0.03} mm=0.5 mm, or the correct slit size is 1 mm.
Slit sizes for e = 9 mm
locationbTslit size
IMS:YSLIT0111 mm2.0 mm
IMS:YSLIT1132 mm1.0 mm
24&26 (all 4)850 mm5.5 mm

  Past practice re YSLIT11

../TrainingImages/slit11hist.png

  What's the big deal re slit sizes?

So you say, what's wrong with slit being too large? Just allows more beam...
Magnification... Envelopes... Steering fallacy... "Lever arm"...

  Steering vs. focusing

In the sketch below, the blue beam is a centred large-emittance beam. But optics just maps phase space to phase space. The red beam (with green center) is a subspace of the blue and can be thought to represent a poorly-centred, small-emittance beam.

../TrainingImages/steerbeam.png

   quads steer misaligned beams...

This shows that if the beam is misaligned in a quadrupole, that quadrupole will steer, making it difficult to achieve a proper focus. For example, if the beam is displaced by more than a beam radius, the steering effect of a quad is more important than the focusing effect. Under these conditions of poor beam alignment, tuning quads to just maximize beam on the final beam stop is not productive. Good tuning practice is to first steer to correct the beam alignment through the quads, then tune the quads to correct beam size. How do you tell the difference? Look at a profile monitor.

  Tuning knobs

A beam particle, and so therefore also the beam centroid (consider the centroid as the reference particle), can be characterized by two coordinates in the x-direction (x,q), and two in the y-direction (y,f). This means the beam misalignment can in principle be corrected by 4 steering elements. But one cannot just pick any 4, since the elements must be `orthogonal'. In the figure below, steerers 1 and 3 are not orthogonal: downstream of steerer 3 they have exactly the same effect. If the goal is to set up the beam to be aligned downstream of steerer 3, use either 1 and 2 or 2 and 3. On the other hand, if the goal is to align the beam locally between 1 and 3 without affecting alignment downstream of 3, then using 1 and 3 is correct.

../TrainingImages/steerer.png
The beam width can be characterized by 3 parameters in each plane: one can think of these as size, divergence, and emittance. However, the emittance is not a tunable parameter. This leaves a total of 2 parameters in each transverse plane. So in principle a beam can be matched using as few as 4 quadrupoles. Again, one must choose an `orthogonal' set of 4.
../TrainingImages/operator.png
4 steering knobs plus 4 focusing knobs = 8 knobs! Not a trivial task...

  Tuning ISAC

Example: Mass separator to LEBT. Tune IMS:Q11, IMS:Q12, IMS:Q15, IMS:Q16, IMS:XCB14, IMS:YCB14, IMS:XCB18, IMS:YCB18. How long does it take to maximize transmission through IMS slits 24 and 26?
Let's say you are looking at current on IMS:FC34, and ignoring the wire scanners. Let's say each knob is evaluated at 10 settings, for a second each. So it takes 10 seconds to tune this knob by itself. But to tune 2 knobs, we need to evaluate 10×10=100 settings; it takes about a minute or 2. Then for 8 knobs, it takes 108 seconds, that's 3 years!
Now imagine we actually use the wire scanners at slits 24 and 26. This way we can tell the difference between a steering error and a focusing error. That reduces the dimensionality by 4. So we can do it in 2×104 seconds = 6 hours!
Now imagine we close the slit IMS:YSLIT11 to its proper setting. This achieves 2 things: It puts the beam at the correct location and it makes the beam have the correct size. Now we are down to a dimensionality of 2. 2×102 seconds = 3 minutes!
(Aside: there is no X (vertical) slit at YSLIT11. That was a big oversight. If we had one, we could match out of the separator in a few seconds.)
What about matching from slits 24 and 26 to the rest of ISAC? There are 4 orthogonal slits. Set them to the correct settings and they define the beam in both position and size, reducing the dimensionality to zero. Setup time = 100 seconds. IOW, if a tune brought beam upstairs with given slit settings before, just load it, set the slits, and you are done. The only possible reason it would not work is if something like a HV PS failed.

  Conclusion

  • Use slits at their correct settings.
  • Use wirescanners.
Both of these techniques reduce the number of dimensions of parameter space.








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On 19 Feb 2005, 00:08.